Python · Exception Handling

What does this print? ``` class E(Exception): def init(self, bal, amt): super().init(bal, amt) self.amt = amt try: raise E(100, 250) except E as e: print(e.args, e.amt) ```

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More in Exception Handling

What does this print? (nested try) ``` try: try: raise TypeError except IndexError: print("inner") except TypeError: print("outer") ```

What happens if an exception is raised inside an except (or else / finally) branch — can a later except of the same try catch it?

In a try/except/else block, when does the else branch run?

What does this print? ``` def f(): try: return 1 finally: print("cleanup") print(f()) ```

What does this function return? ``` def f(): try: return "try" finally: return "finally" ```

Why is ordering except branches general-before-specific a bug? ``` try: risky() except Exception: a() except ValueError: b() ```

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What does this print? ``` class E(Exception): def __init__(self, bal, amt): super().__init__(bal, amt) self.amt = amt try: raise E(100, 250) except E as e: print(e.args, e.amt) ```

More in Exception Handling

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What does this print? ``` class E(Exception): def init(self, bal, amt): super().init(bal, amt) self.amt = amt try: raise E(100, 250) except E as e: print(e.args, e.amt) ```