Python · Structural Pattern Matching

Class A has __match_args__ = ("x", "y", "z"). Why is case A(1, y=2, 3): invalid, and what's the correct ordering?

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More in Structural Pattern Matching

What does this print? ``` d = {"a": 1, "b": 2, "c": 3} match d: case {"a": 1}: print("match") case _: print("no") ```

What does this print? ``` match 5: case 1 | 2 | 3: print("low") case 4 | 5 | 6: print("mid") ```

What does this print? ``` match [1, 2]: case (1, 2): print("tuple pat") case [1, 2]: print("list pat") ```

What happens when you run this? ``` x = 0 match "hello": case x: print("matched") case "hello": print("literal") ```

You have a module constant MAX = 100. Why does this always match, printing "hit" even when n is 5? ``` match n: case MAX: print("hit") ```

What does this print? ``` from enum import Enum class C(Enum): RED = 1 BLUE = 2 match C.BLUE: case C.RED: print("red") case C.BLUE: print("blue") ```

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